Leetcode: Reverse Integer

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Program:

class Solution(object):
    def reverse(self, x):
        flag = 0
        list1 =[]
        if x < 0:
            flag = 1
        
        list1[:0]= str(abs(x))
        result = int("".join(list1[::-1]))
        if flag == 1:
            result = result * -1
        if result > 2**31 - 1 or result <= -2**31:
            return 0
        else: 
            return(result)